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1310350548127 is a prime number
BaseRepresentation
bin10011000100010110111…
…110101001110010011111
311122021020120201202222111
4103010112332221302133
5132432044220020002
62441544451454451
7163445464612465
oct23042676516237
94567216652874
101310350548127
114657977a61a5
12191b558b7427
139674760042a
14475c80bc835
15241429793d7
hex13116fa9c9f

1310350548127 has 2 divisors, whose sum is σ = 1310350548128. Its totient is φ = 1310350548126.

The previous prime is 1310350548113. The next prime is 1310350548173. The reversal of 1310350548127 is 7218450530131.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1310350548127 is a prime.

It is a super-3 number, since 3×13103505481273 (a number of 37 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1310350548127.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1310350548107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655175274063 + 655175274064.

It is an arithmetic number, because the mean of its divisors is an integer number (655175274064).

Almost surely, 21310350548127 is an apocalyptic number.

1310350548127 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310350548127 is an equidigital number, since it uses as much as digits as its factorization.

1310350548127 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 100800, while the sum is 40.

The spelling of 1310350548127 in words is "one trillion, three hundred ten billion, three hundred fifty million, five hundred forty-eight thousand, one hundred twenty-seven".