13104000000 has 924 divisors, whose sum is σ = 58210817392. Its totient is φ = 2764800000.

The previous prime is 13103999969. The next prime is 13104000043. The reversal of 13104000000 is 40131.

It is a Harshad number since it is a multiple of its sum of digits (9).

It is a super Niven number, because it is divisible the sum of any subset of its (nonzero) digits.

It is an unprimeable number.

It is a polite number, since it can be written in 83 ways as a sum of consecutive naturals, for example, 1007999994 + ... + 1008000006.

Almost surely, 2^13104000000 is an apocalyptic number.

13104000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13104000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (29105408696).

13104000000 is an abundant number, since it is smaller than the sum of its proper divisors (45106817392).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13104000000 is an frugal number, since it uses more digits than its factorization.

13104000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 76 (or 30 counting only the distinct ones).

The product of its (nonzero) digits is 12, while the sum is 9.

Adding to 13104000000 its reverse (40131), we get a palindrome (13104040131).

Multiplying 13104000000 by its reverse (40131), we get a square (525876624000000 = 22932000²).

The spelling of 13104000000 in words is "thirteen billion, one hundred four million", and thus it is an aban number.