Base | Representation |
---|---|
bin | 1011111010110000010100… |
… | …0100101101011110110001 |
3 | 1201101201210101221102001121 |
4 | 2332230011010231132301 |
5 | 3204144023231403131 |
6 | 43511524115502241 |
7 | 2521510042042333 |
oct | 276540504553661 |
9 | 51351711842047 |
10 | 13104030341041 |
11 | 41a242a562762 |
12 | 15777952b7981 |
13 | 740921480833 |
14 | 33434a457453 |
15 | 17acec63b911 |
hex | beb0512d7b1 |
13104030341041 has 8 divisors (see below), whose sum is σ = 13265357886144. Its totient is φ = 12942784883280.
The previous prime is 13104030341021. The next prime is 13104030341047. The reversal of 13104030341041 is 14014303040131.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13104030341041 - 217 = 13104030209969 is a prime.
It is a super-2 number, since 2×131040303410412 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13104030340997 and 13104030341015.
It is not an unprimeable number, because it can be changed into a prime (13104030341047) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 20200570 + ... + 20839171.
It is an arithmetic number, because the mean of its divisors is an integer number (1658169735768).
Almost surely, 213104030341041 is an apocalyptic number.
It is an amenable number.
13104030341041 is a deficient number, since it is larger than the sum of its proper divisors (161327545103).
13104030341041 is an equidigital number, since it uses as much as digits as its factorization.
13104030341041 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 41043671.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 13104030341041 its reverse (14014303040131), we get a palindrome (27118333381172).
The spelling of 13104030341041 in words is "thirteen trillion, one hundred four billion, thirty million, three hundred forty-one thousand, forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •