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13104031314111 = 36087437175459
BaseRepresentation
bin1011111010110000010100…
…1000011011000010111111
31201101201210110202211212020
42332230011020123002333
53204144024004022421
643511524152411223
72521510053234303
oct276540510330277
951351713684766
1013104031314111
1141a2430067851
1215777956a6b13
1374092173170a
1433434a62bd03
1517acec77edc6
hexbeb0521b0bf

13104031314111 has 8 divisors (see below), whose sum is σ = 17472072888960. Its totient is φ = 8736005307672.

The previous prime is 13104031314043. The next prime is 13104031314131. The reversal of 13104031314111 is 11141313040131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13104031314111 - 29 = 13104031313599 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13104031314131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1761501 + ... + 5413958.

It is an arithmetic number, because the mean of its divisors is an integer number (2184009111120).

Almost surely, 213104031314111 is an apocalyptic number.

13104031314111 is a deficient number, since it is larger than the sum of its proper divisors (4368041574849).

13104031314111 is an equidigital number, since it uses as much as digits as its factorization.

13104031314111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7784205.

The product of its (nonzero) digits is 432, while the sum is 24.

Adding to 13104031314111 its reverse (11141313040131), we get a palindrome (24245344354242).

The spelling of 13104031314111 in words is "thirteen trillion, one hundred four billion, thirty-one million, three hundred fourteen thousand, one hundred eleven".

Divisors: 1 3 608743 1826229 7175459 21526377 4368010438037 13104031314111