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13104042319997 is a prime number
BaseRepresentation
bin1011111010110000010111…
…0010011010000001111101
31201101201211020111000002122
42332230011302122001331
53204144034313214442
643511525224332325
72521510245623366
oct276540562320175
951351736430078
1013104042319997
1141a24362a4722
1215777993140a5
13740923ab6085
1433434bc94b6d
1517aced705dd2
hexbeb05c9a07d

13104042319997 has 2 divisors, whose sum is σ = 13104042319998. Its totient is φ = 13104042319996.

The previous prime is 13104042319969. The next prime is 13104042320003. The reversal of 13104042319997 is 79991324040131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7201032708676 + 5903009611321 = 2683474^2 + 2429611^2 .

It is a cyclic number.

It is not a de Polignac number, because 13104042319997 - 216 = 13104042254461 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13104042319597) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552021159998 + 6552021159999.

It is an arithmetic number, because the mean of its divisors is an integer number (6552021159999).

Almost surely, 213104042319997 is an apocalyptic number.

It is an amenable number.

13104042319997 is a deficient number, since it is larger than the sum of its proper divisors (1).

13104042319997 is an equidigital number, since it uses as much as digits as its factorization.

13104042319997 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1469664, while the sum is 53.

The spelling of 13104042319997 in words is "thirteen trillion, one hundred four billion, forty-two million, three hundred nineteen thousand, nine hundred ninety-seven".