Base | Representation |
---|---|
bin | 1011111010110000010111… |
… | …0010011101100001011111 |
3 | 1201101201211020111201201111 |
4 | 2332230011302131201133 |
5 | 3204144034314144203 |
6 | 43511525224522451 |
7 | 2521510246013164 |
oct | 276540562354137 |
9 | 51351736451644 |
10 | 13104042334303 |
11 | 41a2436304448 |
12 | 1577799320427 |
13 | 740923abc73b |
14 | 33434bc9a06b |
15 | 17aced70a26d |
hex | beb05c9d85f |
13104042334303 has 8 divisors (see below), whose sum is σ = 13140529637760. Its totient is φ = 13067604042240.
The previous prime is 13104042334283. The next prime is 13104042334319. The reversal of 13104042334303 is 30343324040131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13104042334303 - 29 = 13104042333791 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13104042304303) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11717338 + ... + 12786871.
It is an arithmetic number, because the mean of its divisors is an integer number (1642566204720).
Almost surely, 213104042334303 is an apocalyptic number.
13104042334303 is a deficient number, since it is larger than the sum of its proper divisors (36487303457).
13104042334303 is an equidigital number, since it uses as much as digits as its factorization.
13104042334303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 24505697.
The product of its (nonzero) digits is 31104, while the sum is 31.
Adding to 13104042334303 its reverse (30343324040131), we get a palindrome (43447366374434).
The spelling of 13104042334303 in words is "thirteen trillion, one hundred four billion, forty-two million, three hundred thirty-four thousand, three hundred three".
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