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13104104000653 is a prime number
BaseRepresentation
bin1011111010110000100101…
…1101101100110010001101
31201101201222112112201001101
42332230021131230302031
53204144201111010103
643511535310343101
72521511625120361
oct276541135546215
951351875481041
1013104104000653
1141a24680a3276
1215777b5abaa91
13740933800cc3
1433435614d2a1
1517ad03d3ba1d
hexbeb0976cc8d

13104104000653 has 2 divisors, whose sum is σ = 13104104000654. Its totient is φ = 13104104000652.

The previous prime is 13104104000651. The next prime is 13104104000707. The reversal of 13104104000653 is 35600040140131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12368423833129 + 735680167524 = 3516877^2 + 857718^2 .

It is a cyclic number.

It is not a de Polignac number, because 13104104000653 - 21 = 13104104000651 is a prime.

Together with 13104104000651, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13104104000651) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552052000326 + 6552052000327.

It is an arithmetic number, because the mean of its divisors is an integer number (6552052000327).

Almost surely, 213104104000653 is an apocalyptic number.

It is an amenable number.

13104104000653 is a deficient number, since it is larger than the sum of its proper divisors (1).

13104104000653 is an equidigital number, since it uses as much as digits as its factorization.

13104104000653 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 13104104000653 its reverse (35600040140131), we get a palindrome (48704144140784).

The spelling of 13104104000653 in words is "thirteen trillion, one hundred four billion, one hundred four million, six hundred fifty-three", and thus it is an aban number.