Base | Representation |
---|---|
bin | 1011111010110000101000… |
… | …1111101110100110100100 |
3 | 1201101202000110012222222001 |
4 | 2332230022033232212210 |
5 | 3204144212440142200 |
6 | 43511540455415044 |
7 | 2521512144441451 |
oct | 276541217564644 |
9 | 51352013188861 |
10 | 13104117115300 |
11 | 41a2474540522 |
12 | 15777ba384484 |
13 | 740936443453 |
14 | 334357ba4828 |
15 | 17ad0507c76a |
hex | beb0a3ee9a4 |
13104117115300 has 36 divisors (see below), whose sum is σ = 28778535774576. Its totient is φ = 5178494471200.
The previous prime is 13104117115283. The next prime is 13104117115319. The reversal of 13104117115300 is 351171140131.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 789396346 + ... + 789412945.
It is an arithmetic number, because the mean of its divisors is an integer number (799403771516).
Almost surely, 213104117115300 is an apocalyptic number.
13104117115300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13104117115300 is an abundant number, since it is smaller than the sum of its proper divisors (15674418659276).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13104117115300 is a wasteful number, since it uses less digits than its factorization.
13104117115300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1578809388 (or 1578809381 counting only the distinct ones).
The product of its (nonzero) digits is 1260, while the sum is 28.
Adding to 13104117115300 its reverse (351171140131), we get a palindrome (13455288255431).
The spelling of 13104117115300 in words is "thirteen trillion, one hundred four billion, one hundred seventeen million, one hundred fifteen thousand, three hundred".
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