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13104121113300 = 22352731244182463
BaseRepresentation
bin1011111010110000101001…
…1110111110101011010100
31201101202000201202010012010
42332230022132332223110
53204144220001111200
643511541121224220
72521512223432440
oct276541236765324
951352021663163
1013104121113300
1141a2476821258
1215777bb792070
13740937213129
14334358525820
1517ad055bc150
hexbeb0a7bead4

13104121113300 has 288 divisors, whose sum is σ = 44747599970304. Its totient is φ = 2897384832000.

The previous prime is 13104121113289. The next prime is 13104121113329. The reversal of 13104121113300 is 331112140131.

It is a super-3 number, since 3×131041211133003 (a number of 40 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (21).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 158867869 + ... + 158950331.

It is an arithmetic number, because the mean of its divisors is an integer number (155373611008).

Almost surely, 213104121113300 is an apocalyptic number.

13104121113300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13104121113300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (22373799985152).

13104121113300 is an abundant number, since it is smaller than the sum of its proper divisors (31643478857004).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13104121113300 is a wasteful number, since it uses less digits than its factorization.

13104121113300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 84959 (or 84952 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 21.

Adding to 13104121113300 its reverse (331112140131), we get a palindrome (13435233253431).

The spelling of 13104121113300 in words is "thirteen trillion, one hundred four billion, one hundred twenty-one million, one hundred thirteen thousand, three hundred".