1310413301 has 4 divisors (see below), whose sum is σ = 1310993100. Its totient is φ = 1309833504.

The previous prime is 1310413297. The next prime is 1310413303. The reversal of 1310413301 is 1033140131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1033140131 = 31 ⋅33327101.

It can be written as a sum of positive squares in 2 ways, for example, as 492396100 + 818017201 = 22190^2 + 28601^2 .

It is a cyclic number.

It is not a de Polignac number, because 1310413301 - 2² = 1310413297 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 1310413301.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1310413303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 286496 + ... + 291033.

It is an arithmetic number, because the mean of its divisors is an integer number (327748275).

Almost surely, 2^1310413301 is an apocalyptic number.

It is an amenable number.

1310413301 is a deficient number, since it is larger than the sum of its proper divisors (579799).

1310413301 is an equidigital number, since it uses as much as digits as its factorization.

1310413301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 579798.

The product of its (nonzero) digits is 108, while the sum is 17.

The square root of 1310413301 is about 36199.6312274034. The cubic root of 1310413301 is about 1094.2992398536.

Adding to 1310413301 its reverse (1033140131), we get a palindrome (2343553432).

The spelling of 1310413301 in words is "one billion, three hundred ten million, four hundred thirteen thousand, three hundred one".