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1310420143 is a prime number
BaseRepresentation
bin100111000011011…
…0110110010101111
310101022210020111101
41032012312302233
510140431421033
6334010503531
744321246614
oct11606666257
93338706441
101310420143
1161277505a
12306a34ba7
1317b645b46
14c607450b
157a09c97d
hex4e1b6caf

1310420143 has 2 divisors, whose sum is σ = 1310420144. Its totient is φ = 1310420142.

The previous prime is 1310420131. The next prime is 1310420171. The reversal of 1310420143 is 3410240131.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1310420143 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1310420143.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1310420123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655210071 + 655210072.

It is an arithmetic number, because the mean of its divisors is an integer number (655210072).

Almost surely, 21310420143 is an apocalyptic number.

1310420143 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310420143 is an equidigital number, since it uses as much as digits as its factorization.

1310420143 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 19.

The square root of 1310420143 is about 36199.7257310052. The cubic root of 1310420143 is about 1094.3011443882.

Adding to 1310420143 its reverse (3410240131), we get a palindrome (4720660274).

The spelling of 1310420143 in words is "one billion, three hundred ten million, four hundred twenty thousand, one hundred forty-three".