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1310421107 is a prime number
BaseRepresentation
bin100111000011011…
…0111000001110011
310101022210021211002
41032012313001303
510140431433412
6334010512215
744321252462
oct11606670163
93338707732
101310421107
11612775856
12306a3566b
1317b646408
14c60749d9
157a09cdc2
hex4e1b7073

1310421107 has 2 divisors, whose sum is σ = 1310421108. Its totient is φ = 1310421106.

The previous prime is 1310421011. The next prime is 1310421109. The reversal of 1310421107 is 7011240131.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1310421107 - 214 = 1310404723 is a prime.

It is a super-2 number, since 2×13104211072 = 3434406955342210898, which contains 22 as substring.

Together with 1310421109, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1310421109) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655210553 + 655210554.

It is an arithmetic number, because the mean of its divisors is an integer number (655210554).

Almost surely, 21310421107 is an apocalyptic number.

1310421107 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310421107 is an equidigital number, since it uses as much as digits as its factorization.

1310421107 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 168, while the sum is 20.

The square root of 1310421107 is about 36199.7390460208. The cubic root of 1310421107 is about 1094.3014127260.

Adding to 1310421107 its reverse (7011240131), we get a palindrome (8321661238).

The spelling of 1310421107 in words is "one billion, three hundred ten million, four hundred twenty-one thousand, one hundred seven".