Base | Representation |
---|---|
bin | 100111000011011… |
… | …0111001111111101 |
3 | 10101022210100001122 |
4 | 1032012313033331 |
5 | 10140432001023 |
6 | 334010520325 |
7 | 44321255225 |
oct | 11606671775 |
9 | 3338710048 |
10 | 1310422013 |
11 | 6127764aa |
12 | 306a360a5 |
13 | 17b646954 |
14 | c6075085 |
15 | 7a09d2c8 |
hex | 4e1b73fd |
1310422013 has 2 divisors, whose sum is σ = 1310422014. Its totient is φ = 1310422012.
The previous prime is 1310421991. The next prime is 1310422019. The reversal of 1310422013 is 3102240131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1042837849 + 267584164 = 32293^2 + 16358^2 .
It is an emirp because it is prime and its reverse (3102240131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1310422013 - 26 = 1310421949 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1310421982 and 1310422000.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1310422019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655211006 + 655211007.
It is an arithmetic number, because the mean of its divisors is an integer number (655211007).
Almost surely, 21310422013 is an apocalyptic number.
It is an amenable number.
1310422013 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310422013 is an equidigital number, since it uses as much as digits as its factorization.
1310422013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 17.
The square root of 1310422013 is about 36199.7515599210. The cubic root of 1310422013 is about 1094.3016649190.
Adding to 1310422013 its reverse (3102240131), we get a palindrome (4412662144).
The spelling of 1310422013 in words is "one billion, three hundred ten million, four hundred twenty-two thousand, thirteen".
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