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13104230437 is a prime number
BaseRepresentation
bin11000011010001001…
…01011000000100101
31020211020220212202001
430031010223000211
5203314140333222
610004153045301
7642510056314
oct141504530045
936736825661
1013104230437
115614aa6311
1226586b6831
13130ab66c0c
148c453c27b
1551a68ee27
hex30d12b025

13104230437 has 2 divisors, whose sum is σ = 13104230438. Its totient is φ = 13104230436.

The previous prime is 13104230369. The next prime is 13104230497. The reversal of 13104230437 is 73403240131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13053976516 + 50253921 = 114254^2 + 7089^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13104230437 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13104230497) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552115218 + 6552115219.

It is an arithmetic number, because the mean of its divisors is an integer number (6552115219).

Almost surely, 213104230437 is an apocalyptic number.

It is an amenable number.

13104230437 is a deficient number, since it is larger than the sum of its proper divisors (1).

13104230437 is an equidigital number, since it uses as much as digits as its factorization.

13104230437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6048, while the sum is 28.

Adding to 13104230437 its reverse (73403240131), we get a palindrome (86507470568).

The spelling of 13104230437 in words is "thirteen billion, one hundred four million, two hundred thirty thousand, four hundred thirty-seven".