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1310424044432 = 2481901502777
BaseRepresentation
bin10011000100011011010…
…111000001001110010000
311122021102201000202221212
4103010123113001032100
5132432222023410212
62442000035035252
7163450346410436
oct23043327011620
94567381022855
101310424044432
11465825235048
12191b7643bb28
13967598c4479
14475d3b70d56
1524149145e22
hex1311b5c1390

1310424044432 has 10 divisors (see below), whose sum is σ = 2538946586118. Its totient is φ = 655212022208.

The previous prime is 1310424044383. The next prime is 1310424044459. The reversal of 1310424044432 is 2344404240131.

It can be written as a sum of positive squares in only one way, i.e., 1033036435456 + 277387608976 = 1016384^2 + 526676^2 .

It is a super-2 number, since 2×13104240444322 (a number of 25 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40950751373 + ... + 40950751404.

Almost surely, 21310424044432 is an apocalyptic number.

It is an amenable number.

1310424044432 is a deficient number, since it is larger than the sum of its proper divisors (1228522541686).

1310424044432 is an equidigital number, since it uses as much as digits as its factorization.

1310424044432 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 81901502785 (or 81901502779 counting only the distinct ones).

The product of its (nonzero) digits is 36864, while the sum is 32.

Adding to 1310424044432 its reverse (2344404240131), we get a palindrome (3654828284563).

The spelling of 1310424044432 in words is "one trillion, three hundred ten billion, four hundred twenty-four million, forty-four thousand, four hundred thirty-two".

Divisors: 1 2 4 8 16 81901502777 163803005554 327606011108 655212022216 1310424044432