Base | Representation |
---|---|
bin | 1011111010110001010111… |
… | …0000011010110100100011 |
3 | 1201101202111220121110120102 |
4 | 2332230111300122310203 |
5 | 3204200111410000103 |
6 | 43512011554533015 |
7 | 2521520011100063 |
oct | 276542560326443 |
9 | 51352456543512 |
10 | 13104310234403 |
11 | 41a2563553793 |
12 | 1577852b9716b |
13 | 74096745b7cb |
14 | 3343756b53a3 |
15 | 17ad16ec7e88 |
hex | beb15c1ad23 |
13104310234403 has 2 divisors, whose sum is σ = 13104310234404. Its totient is φ = 13104310234402.
The previous prime is 13104310234399. The next prime is 13104310234409. The reversal of 13104310234403 is 30443201340131.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13104310234403 - 22 = 13104310234399 is a prime.
It is not a weakly prime, because it can be changed into another prime (13104310234409) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552155117201 + 6552155117202.
It is an arithmetic number, because the mean of its divisors is an integer number (6552155117202).
Almost surely, 213104310234403 is an apocalyptic number.
13104310234403 is a deficient number, since it is larger than the sum of its proper divisors (1).
13104310234403 is an equidigital number, since it uses as much as digits as its factorization.
13104310234403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 13104310234403 its reverse (30443201340131), we get a palindrome (43547511574534).
The spelling of 13104310234403 in words is "thirteen trillion, one hundred four billion, three hundred ten million, two hundred thirty-four thousand, four hundred three".
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