13104321112333 has 4 divisors (see below), whose sum is σ = 14295623031648. Its totient is φ = 11913019193020.

The previous prime is 13104321112331. The next prime is 13104321112349. The reversal of 13104321112333 is 33321112340131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 13104321112333 - 2¹ = 13104321112331 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13104321112331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 595650959641 + ... + 595650959662.

It is an arithmetic number, because the mean of its divisors is an integer number (3573905757912).

Almost surely, 2^{13104321112333} is an apocalyptic number.

It is an amenable number.

13104321112333 is a deficient number, since it is larger than the sum of its proper divisors (1191301919315).

13104321112333 is a wasteful number, since it uses less digits than its factorization.

13104321112333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1191301919314.

The product of its (nonzero) digits is 3888, while the sum is 28.

Adding to 13104321112333 its reverse (33321112340131), we get a palindrome (46425433452464).

The spelling of 13104321112333 in words is "thirteen trillion, one hundred four billion, three hundred twenty-one million, one hundred twelve thousand, three hundred thirty-three".