1310432440391 has 2 divisors, whose sum is σ = 1310432440392. Its totient is φ = 1310432440390.

The previous prime is 1310432440327. The next prime is 1310432440393. The reversal of 1310432440391 is 1930442340131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1310432440391 - 2⁶ = 1310432440327 is a prime.

It is a super-2 number, since 2×1310432440391² (a number of 25 digits) contains 22 as substring.

Together with 1310432440393, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1310432440393) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655216220195 + 655216220196.

It is an arithmetic number, because the mean of its divisors is an integer number (655216220196).

Almost surely, 2^{1310432440391} is an apocalyptic number.

1310432440391 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310432440391 is an equidigital number, since it uses as much as digits as its factorization.

1310432440391 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 31104, while the sum is 35.

The spelling of 1310432440391 in words is "one trillion, three hundred ten billion, four hundred thirty-two million, four hundred forty thousand, three hundred ninety-one".