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13104325501121 is a prime number
BaseRepresentation
bin1011111010110001011010…
…1010101010000011000001
31201101202112222100002120102
42332230112222222003001
53204200124312013441
643512013302052145
72521520254623341
oct276542652520301
951352488302512
1013104325501121
1141a2571130908
12157785811a055
1374096a67567a
1433437772ad21
1517ad184e169b
hexbeb16aaa0c1

13104325501121 has 2 divisors, whose sum is σ = 13104325501122. Its totient is φ = 13104325501120.

The previous prime is 13104325501117. The next prime is 13104325501123. The reversal of 13104325501121 is 12110552340131.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12960460804096 + 143864697025 = 3600064^2 + 379295^2 .

It is a cyclic number.

It is not a de Polignac number, because 13104325501121 - 22 = 13104325501117 is a prime.

It is a Sophie Germain prime.

Together with 13104325501123, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (13104325501123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552162750560 + 6552162750561.

It is an arithmetic number, because the mean of its divisors is an integer number (6552162750561).

Almost surely, 213104325501121 is an apocalyptic number.

It is an amenable number.

13104325501121 is a deficient number, since it is larger than the sum of its proper divisors (1).

13104325501121 is an equidigital number, since it uses as much as digits as its factorization.

13104325501121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3600, while the sum is 29.

Adding to 13104325501121 its reverse (12110552340131), we get a palindrome (25214877841252).

The spelling of 13104325501121 in words is "thirteen trillion, one hundred four billion, three hundred twenty-five million, five hundred one thousand, one hundred twenty-one".