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131043255141 = 31738890919
BaseRepresentation
bin111101000001011001…
…0010110001101100101
3110112020122000002122010
41322002302112031211
54121334033131031
6140111143424433
712316242201351
oct1720262261545
9415218002563
10131043255141
1150636557167
1221492155119
13c485078076
1464b1c76461
15361e73b246
hex1e82c96365

131043255141 has 16 divisors (see below), whose sum is σ = 185642409600. Its totient is φ = 82223209664.

The previous prime is 131043255047. The next prime is 131043255169. The reversal of 131043255141 is 141552340131.

It is not a de Polignac number, because 131043255141 - 210 = 131043254117 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131043255099 and 131043255108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131043253141) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4430721 + ... + 4460198.

It is an arithmetic number, because the mean of its divisors is an integer number (11602650600).

Almost surely, 2131043255141 is an apocalyptic number.

It is an amenable number.

131043255141 is a deficient number, since it is larger than the sum of its proper divisors (54599154459).

131043255141 is an frugal number, since it uses more digits than its factorization.

131043255141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8890973 (or 8890939 counting only the distinct ones).

The product of its (nonzero) digits is 7200, while the sum is 30.

Adding to 131043255141 its reverse (141552340131), we get a palindrome (272595595272).

The spelling of 131043255141 in words is "one hundred thirty-one billion, forty-three million, two hundred fifty-five thousand, one hundred forty-one".

Divisors: 1 3 17 51 289 867 4913 14739 8890919 26672757 151145623 453436869 2569475591 7708426773 43681085047 131043255141