Search a number
-
+
131043301001550 = 23352773920320641
BaseRepresentation
bin11101110010111011100101…
…011010000000100101001110
3122011222121122221220111121000
4131302323211122000211032
5114134003140024022200
61142412243355121130
736413365105664520
oct3562734532004516
9564877587814530
10131043301001550
113883317413a513
12128450a04431a6
13581743a776422
14245075b36da10
151023b0c4e6300
hex772ee568094e

131043301001550 has 384 divisors, whose sum is σ = 418401304888320. Its totient is φ = 29537801625600.

The previous prime is 131043301001531. The next prime is 131043301001567. The reversal of 131043301001550 is 55100103340131.

It is a happy number.

131043301001550 is a `hidden beast` number, since 1 + 3 + 1 + 0 + 4 + 3 + 3 + 0 + 100 + 1 + 550 = 666.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 6348679230 + ... + 6348699870.

It is an arithmetic number, because the mean of its divisors is an integer number (1089586731480).

Almost surely, 2131043301001550 is an apocalyptic number.

131043301001550 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 131043301001550, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (209200652444160).

131043301001550 is an abundant number, since it is smaller than the sum of its proper divisors (287358003886770).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131043301001550 is a wasteful number, since it uses less digits than its factorization.

131043301001550 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 29945 (or 29934 counting only the distinct ones).

The product of its (nonzero) digits is 2700, while the sum is 27.

Adding to 131043301001550 its reverse (55100103340131), we get a palindrome (186143404341681).

The spelling of 131043301001550 in words is "one hundred thirty-one trillion, forty-three billion, three hundred one million, one thousand, five hundred fifty".