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13104331315909 is a prime number
BaseRepresentation
bin1011111010110001011100…
…0000110101101011000101
31201101202120101021111221221
42332230113000311223011
53204200132304102114
643512014030440341
72521520355222151
oct276542700655305
951352511244857
1013104331315909
1141a2574442619
12157785a0630b1
1374096b930282
14334378402061
1517ad18c8e524
hexbeb17035ac5

13104331315909 has 2 divisors, whose sum is σ = 13104331315910. Its totient is φ = 13104331315908.

The previous prime is 13104331315891. The next prime is 13104331315919. The reversal of 13104331315909 is 90951313340131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12232156502500 + 872174813409 = 3497450^2 + 933903^2 .

It is a cyclic number.

It is not a de Polignac number, because 13104331315909 - 219 = 13104330791621 is a prime.

It is a super-2 number, since 2×131043313159092 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13104331315919) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552165657954 + 6552165657955.

It is an arithmetic number, because the mean of its divisors is an integer number (6552165657955).

Almost surely, 213104331315909 is an apocalyptic number.

It is an amenable number.

13104331315909 is a deficient number, since it is larger than the sum of its proper divisors (1).

13104331315909 is an equidigital number, since it uses as much as digits as its factorization.

13104331315909 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 131220, while the sum is 43.

The spelling of 13104331315909 in words is "thirteen trillion, one hundred four billion, three hundred thirty-one million, three hundred fifteen thousand, nine hundred nine".