Base | Representation |
---|---|
bin | 1011111010110001011100… |
… | …0001010001110001001101 |
3 | 1201101202120101111100211011 |
4 | 2332230113001101301031 |
5 | 3204200132321242424 |
6 | 43512014033125221 |
7 | 2521520356211521 |
oct | 276542701216115 |
9 | 51352511440734 |
10 | 13104331430989 |
11 | 41a2574511027 |
12 | 157785a0b9811 |
13 | 74096b970776 |
14 | 334378431d81 |
15 | 17ad18cb3694 |
hex | beb17051c4d |
13104331430989 has 2 divisors, whose sum is σ = 13104331430990. Its totient is φ = 13104331430988.
The previous prime is 13104331430947. The next prime is 13104331431119. The reversal of 13104331430989 is 98903413340131.
13104331430989 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12186787757764 + 917543673225 = 3490958^2 + 957885^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13104331430989 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13104331490989) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552165715494 + 6552165715495.
It is an arithmetic number, because the mean of its divisors is an integer number (6552165715495).
Almost surely, 213104331430989 is an apocalyptic number.
It is an amenable number.
13104331430989 is a deficient number, since it is larger than the sum of its proper divisors (1).
13104331430989 is an equidigital number, since it uses as much as digits as its factorization.
13104331430989 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 839808, while the sum is 49.
The spelling of 13104331430989 in words is "thirteen trillion, one hundred four billion, three hundred thirty-one million, four hundred thirty thousand, nine hundred eighty-nine".
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