Base | Representation |
---|---|
bin | 1011111010110001011100… |
… | …0001010001110011001111 |
3 | 1201101202120101111100222222 |
4 | 2332230113001101303033 |
5 | 3204200132321243434 |
6 | 43512014033125555 |
7 | 2521520356212065 |
oct | 276542701216317 |
9 | 51352511440888 |
10 | 13104331431119 |
11 | 41a2574511135 |
12 | 157785a0b98bb |
13 | 74096b970846 |
14 | 334378432035 |
15 | 17ad18cb372e |
hex | beb17051ccf |
13104331431119 has 2 divisors, whose sum is σ = 13104331431120. Its totient is φ = 13104331431118.
The previous prime is 13104331430989. The next prime is 13104331431179. The reversal of 13104331431119 is 91113413340131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13104331431119 - 232 = 13100036463823 is a prime.
It is a super-2 number, since 2×131043314311192 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13104331431179) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552165715559 + 6552165715560.
It is an arithmetic number, because the mean of its divisors is an integer number (6552165715560).
Almost surely, 213104331431119 is an apocalyptic number.
13104331431119 is a deficient number, since it is larger than the sum of its proper divisors (1).
13104331431119 is an equidigital number, since it uses as much as digits as its factorization.
13104331431119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11664, while the sum is 35.
The spelling of 13104331431119 in words is "thirteen trillion, one hundred four billion, three hundred thirty-one million, four hundred thirty-one thousand, one hundred nineteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •