Base | Representation |
---|---|
bin | 11101110010111011101110… |
… | …011000001001110110111011 |
3 | 122011222122001110010010122120 |
4 | 131302323232120021312323 |
5 | 114134003442041311303 |
6 | 1142412310333052323 |
7 | 36413401614203331 |
oct | 3562735630116673 |
9 | 564878043103576 |
10 | 131043451510203 |
11 | 38833241099931 |
12 | 128451229270a3 |
13 | 58174629c29bb |
14 | 245077334bb51 |
15 | 1023b1a826553 |
hex | 772eee609dbb |
131043451510203 has 4 divisors (see below), whose sum is σ = 174724602013608. Its totient is φ = 87362301006800.
The previous prime is 131043451510201. The next prime is 131043451510217. The reversal of 131043451510203 is 302015154340131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131043451510203 - 21 = 131043451510201 is a prime.
It is not an unprimeable number, because it can be changed into a prime (131043451510201) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21840575251698 + ... + 21840575251703.
It is an arithmetic number, because the mean of its divisors is an integer number (43681150503402).
Almost surely, 2131043451510203 is an apocalyptic number.
131043451510203 is a deficient number, since it is larger than the sum of its proper divisors (43681150503405).
131043451510203 is an equidigital number, since it uses as much as digits as its factorization.
131043451510203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 43681150503404.
The product of its (nonzero) digits is 21600, while the sum is 33.
The spelling of 131043451510203 in words is "one hundred thirty-one trillion, forty-three billion, four hundred fifty-one million, five hundred ten thousand, two hundred three".
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