Base | Representation |
---|---|
bin | 1011111010110001100000… |
… | …1100110111000010010011 |
3 | 1201101202121202202222202111 |
4 | 2332230120030313002103 |
5 | 3204200202404310220 |
6 | 43512020021530151 |
7 | 2521521016502623 |
oct | 276543014670223 |
9 | 51352552688674 |
10 | 13104351244435 |
11 | 41a2584714180 |
12 | 1577864873957 |
13 | 740972ab9cb9 |
14 | 33437ad0c883 |
15 | 17ad1a8c915a |
hex | beb18337093 |
13104351244435 has 64 divisors (see below), whose sum is σ = 18630349774848. Its totient is φ = 8754860160000.
The previous prime is 13104351244417. The next prime is 13104351244451. The reversal of 13104351244435 is 53444215340131.
13104351244435 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13104351244435 - 231 = 13102203760787 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 53250 + ... + 5119720.
It is an arithmetic number, because the mean of its divisors is an integer number (291099215232).
Almost surely, 213104351244435 is an apocalyptic number.
13104351244435 is a deficient number, since it is larger than the sum of its proper divisors (5525998530413).
13104351244435 is a wasteful number, since it uses less digits than its factorization.
13104351244435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5066596.
The product of its (nonzero) digits is 345600, while the sum is 40.
Adding to 13104351244435 its reverse (53444215340131), we get a palindrome (66548566584566).
The spelling of 13104351244435 in words is "thirteen trillion, one hundred four billion, three hundred fifty-one million, two hundred forty-four thousand, four hundred thirty-five".
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