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13104400031244 = 2232364011111979
BaseRepresentation
bin1011111010110001101100…
…0110111101111000001100
31201101202202011120121200100
42332230123012331320030
53204200302401444434
643512024523331100
72521522151255334
oct276543306757014
951352664517610
1013104400031244
1141a25aa206455
121577879080a90
1374097cc3c132
143343835ac0c4
1517ad1ed14699
hexbeb1b1bde0c

13104400031244 has 18 divisors (see below), whose sum is σ = 33125011190180. Its totient is φ = 4368133343736.

The previous prime is 13104400031213. The next prime is 13104400031297. The reversal of 13104400031244 is 44213000440131.

13104400031244 is a `hidden beast` number, since 1 + 3 + 10 + 4 + 400 + 0 + 3 + 1 + 244 = 666.

It is a tau number, because it is divible by the number of its divisors (18).

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 182005555954 + ... + 182005556025.

Almost surely, 213104400031244 is an apocalyptic number.

It is an amenable number.

13104400031244 is an abundant number, since it is smaller than the sum of its proper divisors (20020611158936).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13104400031244 is a wasteful number, since it uses less digits than its factorization.

13104400031244 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 364011111989 (or 364011111984 counting only the distinct ones).

The product of its (nonzero) digits is 4608, while the sum is 27.

Adding to 13104400031244 its reverse (44213000440131), we get a palindrome (57317400471375).

The spelling of 13104400031244 in words is "thirteen trillion, one hundred four billion, four hundred million, thirty-one thousand, two hundred forty-four".

Divisors: 1 2 3 4 6 9 12 18 36 364011111979 728022223958 1092033335937 1456044447916 2184066671874 3276100007811 4368133343748 6552200015622 13104400031244