1310440031 has 2 divisors, whose sum is σ = 1310440032. Its totient is φ = 1310440030.

The previous prime is 1310439997. The next prime is 1310440067. The reversal of 1310440031 is 1300440131.

It is a weak prime.

It is an emirp because it is prime and its reverse (1300440131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1310440031 - 2²² = 1306245727 is a prime.

It is a super-2 number, since 2×1310440031² = 3434506149694561922, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1310439991 and 1310440009.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1310442031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655220015 + 655220016.

It is an arithmetic number, because the mean of its divisors is an integer number (655220016).

Almost surely, 2^1310440031 is an apocalyptic number.

1310440031 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310440031 is an equidigital number, since it uses as much as digits as its factorization.

1310440031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 1310440031 is about 36200.0004281768. Note that the first 3 decimals coincide. The cubic root of 1310440031 is about 1094.3066803610.

Adding to 1310440031 its reverse (1300440131), we get a palindrome (2610880162).

It can be divided in two parts, 13104 and 40031, that added together give a palindrome (53135).

The spelling of 1310440031 in words is "one billion, three hundred ten million, four hundred forty thousand, thirty-one".