1310440130 has 32 divisors (see below), whose sum is σ = 2378934144. Its totient is φ = 519716736.

The previous prime is 1310440097. The next prime is 1310440133. The reversal of 1310440130 is 310440131.

It is a junction number, because it is equal to n+sod(n) for n = 1310440099 and 1310440108.

It is not an unprimeable number, because it can be changed into a prime (1310440133) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1005059 + ... + 1006361.

It is an arithmetic number, because the mean of its divisors is an integer number (74341692).

Almost surely, 2^1310440130 is an apocalyptic number.

1310440130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1310440130 is a deficient number, since it is larger than the sum of its proper divisors (1068494014).

1310440130 is a wasteful number, since it uses less digits than its factorization.

1310440130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2090.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 1310440130 is about 36200.0017955801. The cubic root of 1310440130 is about 1094.3067079183.

Adding to 1310440130 its reverse (310440131), we get a palindrome (1620880261).

Subtracting from 1310440130 its reverse (310440131), we obtain a palindrome (999999999).

The spelling of 1310440130 in words is "one billion, three hundred ten million, four hundred forty thousand, one hundred thirty".