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13104402502141 = 40351324760291
BaseRepresentation
bin1011111010110001101101…
…0000011001000111111101
31201101202202100020011010001
42332230123100121013331
53204200304020032031
643512025052314301
72521522211256166
oct276543320310775
951352670204101
1013104402502141
1141a2600643915
121577879a72991
137409805c59c2
14334383a5276d
1517ad20151861
hexbeb1b4191fd

13104402502141 has 4 divisors (see below), whose sum is σ = 13104727302784. Its totient is φ = 13104077701500.

The previous prime is 13104402502117. The next prime is 13104402502151. The reversal of 13104402502141 is 14120520440131.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13104402502141 - 29 = 13104402501629 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13104402502151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 162339795 + ... + 162420496.

It is an arithmetic number, because the mean of its divisors is an integer number (3276181825696).

Almost surely, 213104402502141 is an apocalyptic number.

It is an amenable number.

13104402502141 is a deficient number, since it is larger than the sum of its proper divisors (324800643).

13104402502141 is an equidigital number, since it uses as much as digits as its factorization.

13104402502141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 324800642.

The product of its (nonzero) digits is 3840, while the sum is 28.

Adding to 13104402502141 its reverse (14120520440131), we get a palindrome (27224922942272).

The spelling of 13104402502141 in words is "thirteen trillion, one hundred four billion, four hundred two million, five hundred two thousand, one hundred forty-one".

Divisors: 1 40351 324760291 13104402502141