Base | Representation |
---|---|
bin | 1011111010110001101101… |
… | …0000011100010101110000 |
3 | 1201101202202100020211011212 |
4 | 2332230123100130111300 |
5 | 3204200304020442222 |
6 | 43512025052455252 |
7 | 2521522211342453 |
oct | 276543320342560 |
9 | 51352670224155 |
10 | 13104402515312 |
11 | 41a26006527a9 |
12 | 1577879a7a528 |
13 | 7409805cb9b4 |
14 | 334383a5749a |
15 | 17ad201556e2 |
hex | beb1b41c570 |
13104402515312 has 20 divisors (see below), whose sum is σ = 25392302265576. Its totient is φ = 6551550317760.
The previous prime is 13104402515161. The next prime is 13104402515327. The reversal of 13104402515312 is 21351520440131.
13104402515312 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40517639 + ... + 40839782.
Almost surely, 213104402515312 is an apocalyptic number.
It is an amenable number.
13104402515312 is a deficient number, since it is larger than the sum of its proper divisors (12287899750264).
13104402515312 is a wasteful number, since it uses less digits than its factorization.
13104402515312 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 81367496 (or 81367490 counting only the distinct ones).
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 13104402515312 its reverse (21351520440131), we get a palindrome (34455922955443).
The spelling of 13104402515312 in words is "thirteen trillion, one hundred four billion, four hundred two million, five hundred fifteen thousand, three hundred twelve".
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