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1310442133030 = 25131044213303
BaseRepresentation
bin10011000100011100011…
…100000001011000100110
311122021110222001202211221
4103010130130001120212
5132432241141224110
62442001522450554
7163450656226042
oct23043434013046
94567428052757
101310442133030
1146583446a2a8
12191b80503a5a
1396760588894
14475d631d022
152414aa1a7da
hex1311c701626

1310442133030 has 8 divisors (see below), whose sum is σ = 2358795839472. Its totient is φ = 524176853208.

The previous prime is 1310442132977. The next prime is 1310442133051. The reversal of 1310442133030 is 303312440131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 1310442132986 and 1310442133004.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 65522106642 + ... + 65522106661.

It is an arithmetic number, because the mean of its divisors is an integer number (294849479934).

Almost surely, 21310442133030 is an apocalyptic number.

1310442133030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1310442133030 is a deficient number, since it is larger than the sum of its proper divisors (1048353706442).

1310442133030 is a wasteful number, since it uses less digits than its factorization.

1310442133030 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 131044213310.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 1310442133030 its reverse (303312440131), we get a palindrome (1613754573161).

The spelling of 1310442133030 in words is "one trillion, three hundred ten billion, four hundred forty-two million, one hundred thirty-three thousand, thirty".

Divisors: 1 2 5 10 131044213303 262088426606 655221066515 1310442133030