Base | Representation |
---|---|
bin | 11101110010111100011110… |
… | …001001111111000001000110 |
3 | 122011222201010022110020002012 |
4 | 131302330132021333001012 |
5 | 114134012112243232100 |
6 | 1142412522050014222 |
7 | 36413430516500153 |
oct | 3562743611770106 |
9 | 564881108406065 |
10 | 131044253102150 |
11 | 38833612617813 |
12 | 12845307277372 |
13 | 581755cab236b |
14 | 245080b9ad22a |
15 | 1023b65db5135 |
hex | 772f1e27f046 |
131044253102150 has 48 divisors (see below), whose sum is σ = 252370557964800. Its totient is φ = 50565366216960.
The previous prime is 131044253102143. The next prime is 131044253102167. The reversal of 131044253102150 is 51201352440131.
It is a super-3 number, since 3×1310442531021503 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 38387462 + ... + 41661561.
It is an arithmetic number, because the mean of its divisors is an integer number (5257719957600).
Almost surely, 2131044253102150 is an apocalyptic number.
131044253102150 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131044253102150 is a deficient number, since it is larger than the sum of its proper divisors (121326304862650).
131044253102150 is a wasteful number, since it uses less digits than its factorization.
131044253102150 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 80050193 (or 80050188 counting only the distinct ones).
The product of its (nonzero) digits is 14400, while the sum is 32.
The spelling of 131044253102150 in words is "one hundred thirty-one trillion, forty-four billion, two hundred fifty-three million, one hundred two thousand, one hundred fifty".
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