Base | Representation |
---|---|
bin | 10011000100011100011… |
… | …111101000100101000001 |
3 | 11122021111000211212211221 |
4 | 103010130133220211001 |
5 | 132432241412030001 |
6 | 2442001555035041 |
7 | 163451000251636 |
oct | 23043437504501 |
9 | 4567430755757 |
10 | 1310443080001 |
11 | 465834a56820 |
12 | 191b8089ba81 |
13 | 9676082a913 |
14 | 475d64c818d |
15 | 2414ab561a1 |
hex | 1311c7e8941 |
1310443080001 has 8 divisors (see below), whose sum is σ = 1491729672384. Its totient is φ = 1139515721520.
The previous prime is 1310443079993. The next prime is 1310443080007. The reversal of 1310443080001 is 1000803440131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1310443080001 - 23 = 1310443079993 is a prime.
It is a super-2 number, since 2×13104430800012 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1310443080007) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2589808206 + ... + 2589808711.
It is an arithmetic number, because the mean of its divisors is an integer number (186466209048).
Almost surely, 21310443080001 is an apocalyptic number.
1310443080001 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
1310443080001 is a deficient number, since it is larger than the sum of its proper divisors (181286592383).
1310443080001 is a wasteful number, since it uses less digits than its factorization.
1310443080001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5179616951.
The product of its (nonzero) digits is 1152, while the sum is 25.
The spelling of 1310443080001 in words is "one trillion, three hundred ten billion, four hundred forty-three million, eighty thousand, one".
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