Base | Representation |
---|---|
bin | 1011111010110001110110… |
… | …1111111110010011100101 |
3 | 1201101202212020221111110112 |
4 | 2332230131233332103211 |
5 | 3204200400222212313 |
6 | 43512033145102405 |
7 | 2521523226660641 |
oct | 276543557762345 |
9 | 51352766844415 |
10 | 13104444335333 |
11 | 41a26222167aa |
12 | 157788ba87a05 |
13 | 740989181a80 |
14 | 334389421c21 |
15 | 17ad23b668a8 |
hex | beb1dbfe4e5 |
13104444335333 has 8 divisors (see below), whose sum is σ = 14237367706968. Its totient is φ = 11989362276864.
The previous prime is 13104444335329. The next prime is 13104444335351. The reversal of 13104444335333 is 33353344440131.
It can be written as a sum of positive squares in 4 ways, for example, as 512968223524 + 12591476111809 = 716218^2 + 3548447^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13104444335333 - 22 = 13104444335329 is a prime.
It is a super-2 number, since 2×131044443353332 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13104444335383) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4460326760 + ... + 4460329697.
It is an arithmetic number, because the mean of its divisors is an integer number (1779670963371).
Almost surely, 213104444335333 is an apocalyptic number.
13104444335333 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
13104444335333 is a deficient number, since it is larger than the sum of its proper divisors (1132923371635).
13104444335333 is a wasteful number, since it uses less digits than its factorization.
13104444335333 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8920656583.
The product of its (nonzero) digits is 933120, while the sum is 41.
Adding to 13104444335333 its reverse (33353344440131), we get a palindrome (46457788775464).
The spelling of 13104444335333 in words is "thirteen trillion, one hundred four billion, four hundred forty-four million, three hundred thirty-five thousand, three hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •