131045400004321 has 4 divisors (see below), whose sum is σ = 142958618186544. Its totient is φ = 119132181822100.

The previous prime is 131045400004313. The next prime is 131045400004357. The reversal of 131045400004321 is 123400004540131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131045400004321 - 2³ = 131045400004313 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 131045400004321.

It is not an unprimeable number, because it can be changed into a prime (131045400304321) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5956609091095 + ... + 5956609091116.

It is an arithmetic number, because the mean of its divisors is an integer number (35739654546636).

Almost surely, 2^{131045400004321} is an apocalyptic number.

131045400004321 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

131045400004321 is a deficient number, since it is larger than the sum of its proper divisors (11913218182223).

131045400004321 is a wasteful number, since it uses less digits than its factorization.

131045400004321 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11913218182222.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 131045400004321 its reverse (123400004540131), we get a palindrome (254445404544452).

The spelling of 131045400004321 in words is "one hundred thirty-one trillion, forty-five billion, four hundred million, four thousand, three hundred twenty-one".