Base | Representation |
---|---|
bin | 1011111010110010010001… |
… | …0011111000110000101110 |
3 | 1201101210010221002000202221 |
4 | 2332230210103320300232 |
5 | 3204201111412204402 |
6 | 43512052120305554 |
7 | 2521526034425245 |
oct | 276544423706056 |
9 | 51353127060687 |
10 | 13104554413102 |
11 | 41a2679370869 |
12 | 15779009122ba |
13 | 7409a5c13649 |
14 | 334399cb795c |
15 | 17ad2d65c337 |
hex | beb244f8c2e |
13104554413102 has 4 divisors (see below), whose sum is σ = 19656831619656. Its totient is φ = 6552277206550.
The previous prime is 13104554413087. The next prime is 13104554413121. The reversal of 13104554413102 is 20131445540131.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×131045544131022 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3276138603274 + ... + 3276138603277.
It is an arithmetic number, because the mean of its divisors is an integer number (4914207904914).
Almost surely, 213104554413102 is an apocalyptic number.
13104554413102 is a deficient number, since it is larger than the sum of its proper divisors (6552277206554).
13104554413102 is an equidigital number, since it uses as much as digits as its factorization.
13104554413102 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6552277206553.
The product of its (nonzero) digits is 28800, while the sum is 34.
Adding to 13104554413102 its reverse (20131445540131), we get a palindrome (33235999953233).
The spelling of 13104554413102 in words is "thirteen trillion, one hundred four billion, five hundred fifty-four million, four hundred thirteen thousand, one hundred two".
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