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13104703 = 95313751
BaseRepresentation
bin110001111111…
…011000111111
3220122210021101
4301333120333
511323322303
61144513531
7216250063
oct61773077
926583241
1013104703
117440837
12447b8a7
13293aa81
141a51aa3
15123cd1d
hexc7f63f

13104703 has 4 divisors (see below), whose sum is σ = 13119408. Its totient is φ = 13090000.

The previous prime is 13104677. The next prime is 13104709. The reversal of 13104703 is 30740131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30740131 = 171808243.

It is a cyclic number.

It is not a de Polignac number, because 13104703 - 29 = 13104191 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13104709) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5923 + ... + 7828.

It is an arithmetic number, because the mean of its divisors is an integer number (3279852).

Almost surely, 213104703 is an apocalyptic number.

13104703 is a deficient number, since it is larger than the sum of its proper divisors (14705).

13104703 is an equidigital number, since it uses as much as digits as its factorization.

13104703 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14704.

The product of its (nonzero) digits is 252, while the sum is 19.

The square root of 13104703 is about 3620.0418505868. The cubic root of 13104703 is about 235.7630425880.

Adding to 13104703 its reverse (30740131), we get a palindrome (43844834).

The spelling of 13104703 in words is "thirteen million, one hundred four thousand, seven hundred three".

Divisors: 1 953 13751 13104703