Base | Representation |
---|---|
bin | 11101110011000001110100… |
… | …011010011001101000001011 |
3 | 122012000020221111020200210101 |
4 | 131303001310122121220023 |
5 | 114134110342233311243 |
6 | 1142415311531230231 |
7 | 36414023022566104 |
oct | 3563016432315013 |
9 | 565006844220711 |
10 | 131049995213323 |
11 | 38835a9991693a |
12 | 1284644a2a8377 |
13 | 5817c66605a94 |
14 | 2450bd444b3ab |
15 | 1023da005b54d |
hex | 773074699a0b |
131049995213323 has 2 divisors, whose sum is σ = 131049995213324. Its totient is φ = 131049995213322.
The previous prime is 131049995213243. The next prime is 131049995213353. The reversal of 131049995213323 is 323312599940131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131049995213323 - 233 = 131041405278731 is a prime.
It is not a weakly prime, because it can be changed into another prime (131049995213353) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65524997606661 + 65524997606662.
It is an arithmetic number, because the mean of its divisors is an integer number (65524997606662).
Almost surely, 2131049995213323 is an apocalyptic number.
131049995213323 is a deficient number, since it is larger than the sum of its proper divisors (1).
131049995213323 is an equidigital number, since it uses as much as digits as its factorization.
131049995213323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4723920, while the sum is 55.
The spelling of 131049995213323 in words is "one hundred thirty-one trillion, forty-nine billion, nine hundred ninety-five million, two hundred thirteen thousand, three hundred twenty-three".
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