131050250021111 has 4 divisors (see below), whose sum is σ = 135569224159800. Its totient is φ = 126531275882424.

The previous prime is 131050250021071. The next prime is 131050250021137. The reversal of 131050250021111 is 111120052050131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131050250021111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131050250027111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2259487069301 + ... + 2259487069358.

It is an arithmetic number, because the mean of its divisors is an integer number (33892306039950).

Almost surely, 2^{131050250021111} is an apocalyptic number.

131050250021111 is a deficient number, since it is larger than the sum of its proper divisors (4518974138689).

131050250021111 is an equidigital number, since it uses as much as digits as its factorization.

131050250021111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4518974138688.

The product of its (nonzero) digits is 300, while the sum is 23.

The spelling of 131050250021111 in words is "one hundred thirty-one trillion, fifty billion, two hundred fifty million, twenty-one thousand, one hundred eleven".