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13105323424577 is a prime number
BaseRepresentation
bin1011111010110101001000…
…1001011011101101000001
31201101212010112002212012102
42332231102021123231001
53204204200244041302
643512300311040145
72521554063055226
oct276552211335501
951355115085172
1013105323424577
1141a2a3346653a
121577a96370055
13740a99336617
1433443009794d
1517ad75e12702
hexbeb5225bb41

13105323424577 has 2 divisors, whose sum is σ = 13105323424578. Its totient is φ = 13105323424576.

The previous prime is 13105323424499. The next prime is 13105323424579. The reversal of 13105323424577 is 77542432350131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12983979882241 + 121343542336 = 3603329^2 + 348344^2 .

It is a cyclic number.

It is not a de Polignac number, because 13105323424577 - 220 = 13105322376001 is a prime.

Together with 13105323424579, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13105323424579) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552661712288 + 6552661712289.

It is an arithmetic number, because the mean of its divisors is an integer number (6552661712289).

Almost surely, 213105323424577 is an apocalyptic number.

It is an amenable number.

13105323424577 is a deficient number, since it is larger than the sum of its proper divisors (1).

13105323424577 is an equidigital number, since it uses as much as digits as its factorization.

13105323424577 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2116800, while the sum is 47.

The spelling of 13105323424577 in words is "thirteen trillion, one hundred five billion, three hundred twenty-three million, four hundred twenty-four thousand, five hundred seventy-seven".