Base | Representation |
---|---|
bin | 1011111010110101001010… |
… | …1010001100010001010011 |
3 | 1201101212011010021011002101 |
4 | 2332231102222030101103 |
5 | 3204204204443341430 |
6 | 43512301215101231 |
7 | 2521554226052620 |
oct | 276552252142123 |
9 | 51355133234071 |
10 | 13105332012115 |
11 | 41a2a382a1482 |
12 | 1577a99211817 |
13 | 740a9b0522c5 |
14 | 334431291347 |
15 | 17ad76a5bdca |
hex | beb52a8c453 |
13105332012115 has 16 divisors (see below), whose sum is σ = 18754462706688. Its totient is φ = 8595795406176.
The previous prime is 13105332012029. The next prime is 13105332012121. The reversal of 13105332012115 is 51121023350131.
13105332012115 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 13105332012115 - 223 = 13105323623507 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8139956967 + ... + 8139958576.
It is an arithmetic number, because the mean of its divisors is an integer number (1172153919168).
Almost surely, 213105332012115 is an apocalyptic number.
13105332012115 is a deficient number, since it is larger than the sum of its proper divisors (5649130694573).
13105332012115 is a wasteful number, since it uses less digits than its factorization.
13105332012115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16279915578.
The product of its (nonzero) digits is 2700, while the sum is 28.
Adding to 13105332012115 its reverse (51121023350131), we get a palindrome (64226355362246).
The spelling of 13105332012115 in words is "thirteen trillion, one hundred five billion, three hundred thirty-two million, twelve thousand, one hundred fifteen".
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