Base | Representation |
---|---|
bin | 1011111010110101001010… |
… | …1010101100101111010111 |
3 | 1201101212011010111220112011 |
4 | 2332231102222230233113 |
5 | 3204204210012120421 |
6 | 43512301222005051 |
7 | 2521554230145433 |
oct | 276552252545727 |
9 | 51355133456464 |
10 | 13105332145111 |
11 | 41a2a38382398 |
12 | 1577a99276787 |
13 | 740a9b09a9bb |
14 | 3344312c79c3 |
15 | 17ad76a864e1 |
hex | beb52aacbd7 |
13105332145111 has 2 divisors, whose sum is σ = 13105332145112. Its totient is φ = 13105332145110.
The previous prime is 13105332145067. The next prime is 13105332145123. The reversal of 13105332145111 is 11154123350131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13105332145111 - 235 = 13070972406743 is a prime.
It is a super-2 number, since 2×131053321451112 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13105332146111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552666072555 + 6552666072556.
It is an arithmetic number, because the mean of its divisors is an integer number (6552666072556).
Almost surely, 213105332145111 is an apocalyptic number.
13105332145111 is a deficient number, since it is larger than the sum of its proper divisors (1).
13105332145111 is an equidigital number, since it uses as much as digits as its factorization.
13105332145111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5400, while the sum is 31.
Adding to 13105332145111 its reverse (11154123350131), we get a palindrome (24259455495242).
The spelling of 13105332145111 in words is "thirteen trillion, one hundred five billion, three hundred thirty-two million, one hundred forty-five thousand, one hundred eleven".
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