Base | Representation |
---|---|
bin | 1011111010110101011100… |
… | …0010101001000101000011 |
3 | 1201101212100020121021021010 |
4 | 2332231113002221011003 |
5 | 3204204332303433220 |
6 | 43512312402532003 |
7 | 2521556111002011 |
oct | 276552702510503 |
9 | 51355306537233 |
10 | 13105405530435 |
11 | 41a2a75845919 |
12 | 1577ab9967003 |
13 | 740ab035337a |
14 | 33443ad4b8b1 |
15 | 17ad7d2301e0 |
hex | beb570a9143 |
13105405530435 has 64 divisors (see below), whose sum is σ = 21769534080000. Its totient is φ = 6728836907520.
The previous prime is 13105405530403. The next prime is 13105405530467. The reversal of 13105405530435 is 53403550450131.
13105405530435 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (13105405530403) and next prime (13105405530467).
It is not a de Polignac number, because 13105405530435 - 25 = 13105405530403 is a prime.
It is a super-2 number, since 2×131054055304352 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13105405530393 and 13105405530402.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 8662521 + ... + 10062309.
It is an arithmetic number, because the mean of its divisors is an integer number (340148970000).
Almost surely, 213105405530435 is an apocalyptic number.
13105405530435 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13105405530435 is a deficient number, since it is larger than the sum of its proper divisors (8664128549565).
13105405530435 is a wasteful number, since it uses less digits than its factorization.
13105405530435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1400076.
The product of its (nonzero) digits is 270000, while the sum is 39.
Adding to 13105405530435 its reverse (53403550450131), we get a palindrome (66508955980566).
The spelling of 13105405530435 in words is "thirteen trillion, one hundred five billion, four hundred five million, five hundred thirty thousand, four hundred thirty-five".
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