13105413535 has 4 divisors (see below), whose sum is σ = 15726496248. Its totient is φ = 10484330824.

The previous prime is 13105413523. The next prime is 13105413551. The reversal of 13105413535 is 53531450131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13105413535 - 2¹³ = 13105405343 is a prime.

It is a super-2 number, since 2×13105413535² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13105413497 and 13105413506.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1310541349 + ... + 1310541358.

It is an arithmetic number, because the mean of its divisors is an integer number (3931624062).

Almost surely, 2^13105413535 is an apocalyptic number.

13105413535 is a deficient number, since it is larger than the sum of its proper divisors (2621082713).

13105413535 is an equidigital number, since it uses as much as digits as its factorization.

13105413535 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2621082712.

The product of its (nonzero) digits is 13500, while the sum is 31.

Adding to 13105413535 its reverse (53531450131), we get a palindrome (66636863666).

The spelling of 13105413535 in words is "thirteen billion, one hundred five million, four hundred thirteen thousand, five hundred thirty-five".