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13105434542 = 27338939587
BaseRepresentation
bin11000011010010010…
…10000111110101110
31020211100012001110112
430031021100332232
5203314442401132
610004234540022
7642523232654
oct141511207656
936740161415
1013105434542
115615748a42
122658b97612
13130b198cc5
148c4772dd4
1551a82bab2
hex30d250fae

13105434542 has 8 divisors (see below), whose sum is σ = 19684972776. Its totient is φ = 6543776952.

The previous prime is 13105434541. The next prime is 13105434619. The reversal of 13105434542 is 24543450131.

13105434542 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 13105434499 and 13105434508.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13105434541) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4468328 + ... + 4471259.

It is an arithmetic number, because the mean of its divisors is an integer number (2460621597).

Almost surely, 213105434542 is an apocalyptic number.

13105434542 is a deficient number, since it is larger than the sum of its proper divisors (6579538234).

13105434542 is an equidigital number, since it uses as much as digits as its factorization.

13105434542 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8940322.

The product of its (nonzero) digits is 28800, while the sum is 32.

Adding to 13105434542 its reverse (24543450131), we get a palindrome (37648884673).

The spelling of 13105434542 in words is "thirteen billion, one hundred five million, four hundred thirty-four thousand, five hundred forty-two".

Divisors: 1 2 733 1466 8939587 17879174 6552717271 13105434542