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131055014155 = 5136133052967
BaseRepresentation
bin111101000001101111…
…1001101000100001011
3110112021110010111222011
41322003133031010023
54121400040423110
6140112243440351
712316444145242
oct1720337150413
9415243114864
10131055014155
115064215895a
12214960860b7
13c487634470
1464b3657959
1536207b048a
hex1e837cd10b

131055014155 has 16 divisors (see below), whose sum is σ = 172139857344. Its totient is φ = 95192542080.

The previous prime is 131055014147. The next prime is 131055014159. The reversal of 131055014155 is 551410550131.

It is a happy number.

It is not a de Polignac number, because 131055014155 - 23 = 131055014147 is a prime.

It is a super-3 number, since 3×1310550141553 (a number of 34 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (131055014159) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16522519 + ... + 16530448.

It is an arithmetic number, because the mean of its divisors is an integer number (10758741084).

Almost surely, 2131055014155 is an apocalyptic number.

131055014155 is a deficient number, since it is larger than the sum of its proper divisors (41084843189).

131055014155 is a wasteful number, since it uses less digits than its factorization.

131055014155 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33053046.

The product of its (nonzero) digits is 7500, while the sum is 31.

Adding to 131055014155 its reverse (551410550131), we get a palindrome (682465564286).

The spelling of 131055014155 in words is "one hundred thirty-one billion, fifty-five million, fourteen thousand, one hundred fifty-five".

Divisors: 1 5 13 61 65 305 793 3965 33052967 165264835 429688571 2016230987 2148442855 10081154935 26211002831 131055014155