Base | Representation |
---|---|
bin | 10011000100100010111… |
… | …100010001010010000111 |
3 | 11122021202120101111021020 |
4 | 103010202330101102013 |
5 | 132433002110000210 |
6 | 2442020421322223 |
7 | 163453452552345 |
oct | 23044274212207 |
9 | 4567676344236 |
10 | 1310551250055 |
11 | 465890018563 |
12 | 191bb0b66373 |
13 | 9677a072078 |
14 | 47606a04995 |
15 | 241553c1770 |
hex | 13122f11487 |
1310551250055 has 16 divisors (see below), whose sum is σ = 2100906738144. Its totient is φ = 697619087360.
The previous prime is 1310551250053. The next prime is 1310551250069. The reversal of 1310551250055 is 5500521550131.
It is not a de Polignac number, because 1310551250055 - 21 = 1310551250053 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1310551249998 and 1310551250025.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1310551250053) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 83840634 + ... + 83856263.
It is an arithmetic number, because the mean of its divisors is an integer number (131306671134).
Almost surely, 21310551250055 is an apocalyptic number.
1310551250055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1310551250055 is a deficient number, since it is larger than the sum of its proper divisors (790355488089).
1310551250055 is a wasteful number, since it uses less digits than its factorization.
1310551250055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 167697426.
The product of its (nonzero) digits is 18750, while the sum is 33.
The spelling of 1310551250055 in words is "one trillion, three hundred ten billion, five hundred fifty-one million, two hundred fifty thousand, fifty-five".
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