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13106016543 = 35382427777
BaseRepresentation
bin11000011010010110…
…11111000100011111
31020211101021121211010
430031023133010133
5203320120012133
610004255230303
7642531205524
oct141513370437
936741247733
1013106016543
115616006234
122659218393
13130b340b99
148c488514b
1551a8e4263
hex30d2df11f

13106016543 has 8 divisors (see below), whose sum is σ = 17804400048. Its totient is φ = 8572488704.

The previous prime is 13106016541. The next prime is 13106016589. The reversal of 13106016543 is 34561060131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13106016543 - 21 = 13106016541 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13106016543.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13106016541) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 41213730 + ... + 41214047.

It is an arithmetic number, because the mean of its divisors is an integer number (2225550006).

Almost surely, 213106016543 is an apocalyptic number.

13106016543 is a deficient number, since it is larger than the sum of its proper divisors (4698383505).

13106016543 is an equidigital number, since it uses as much as digits as its factorization.

13106016543 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 82427833.

The product of its (nonzero) digits is 6480, while the sum is 30.

Adding to 13106016543 its reverse (34561060131), we get a palindrome (47667076674).

The spelling of 13106016543 in words is "thirteen billion, one hundred six million, sixteen thousand, five hundred forty-three".

Divisors: 1 3 53 159 82427777 247283331 4368672181 13106016543