13108118994767 has 2 divisors, whose sum is σ = 13108118994768. Its totient is φ = 13108118994766.

The previous prime is 13108118994739. The next prime is 13108118994769. The reversal of 13108118994767 is 76749981180131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13108118994767 - 2¹⁸ = 13108118732623 is a prime.

It is a super-3 number, since 3×13108118994767³ (a number of 40 digits) contains 333 as substring.

Together with 13108118994769, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13108118994769) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6554059497383 + 6554059497384.

It is an arithmetic number, because the mean of its divisors is an integer number (6554059497384).

Almost surely, 2^{13108118994767} is an apocalyptic number.

13108118994767 is a deficient number, since it is larger than the sum of its proper divisors (1).

13108118994767 is an equidigital number, since it uses as much as digits as its factorization.

13108118994767 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18289152, while the sum is 65.

The spelling of 13108118994767 in words is "thirteen trillion, one hundred eight billion, one hundred eighteen million, nine hundred ninety-four thousand, seven hundred sixty-seven".